2k^-4*4k^2=8/k^2

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Solution for 2k^-4*4k^2=8/k^2 equation: 



2k^-4*4k^2=8/k^2

We move all terms to the left:

2k^-4*4k^2-(8/k^2)=0



Domain of the equation: k^2)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

2k-4*4k^2-(8/k^2)=0

Wy multiply elements

-16k^2+2k-(8/k^2)=0

We get rid of parentheses

-16k^2+2k-8/k^2=0

We multiply all the terms by the denominator


-16k^2*k^2+2k*k^2-8=0

Wy multiply elements

-16k^4+2k^3-8=0

We do not support ekpression: k^4

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